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Issue C62115 @ escapes are incorrectly handled in strings Submitted by: Kevin Bracey     Appeared in: Compiler 6.21 or before     Fixed in: Compiler 6.30 Problem There are several problems: @@32 outputs a garbled Z-character sequence, rather than a space. @@ with any number less than 256 is treated as that character from the source ("ISO") character set, rather than that ZSCII code. Values of 256 or greater are treated as ZSCII codes, and for values less than 128 the error doesn't matter. Escape sequences giving non-ASCII characters (eg @@169, @'a or @{E1}) are always output as a 4 Z-character sequence, even if the requested character is in the alphabet table (in which case it should occupy 1 or 2 Z-characters). In some cases the escape sequence may even output the wrong character altogether, if other accented characters are in the alphabet table. Solution Apply this patch: --- chars.c~ Wed Apr 28 21:14:39 1999 +++ chars.c Sat Nov 24 09:41:28 2001 @@ -173,7 +173,7 @@ } } for (j=0; j<3; j++) - for (k=0; k<26; k++) + for (k=(j<2?0:1); k<26; k++) { i=(int) ((alphabet[j])[k]); zscii_to_alphabet_grid[i] = k + j*26; iso_to_alphabet_grid[zscii_to_iso_grid[i]] = k + j*26; --- text.c~ Wed Apr 28 21:17:59 1999 +++ text.c Sat Nov 24 17:01:54 2001 @@ -229,7 +229,12 @@ { int lookup_value, in_alphabet; - if (zsc < 0x100) lookup_value = iso_to_alphabet_grid[zsc]; + if (zsc==' ') + { write_z_char(0); + return; + } + + if (zsc < 0x100) lookup_value = zscii_to_alphabet_grid[zsc]; else lookup_value = -1; if (lookup_value >= 0)

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